6a^2+50=40a

Solution for 6a^2+50=40a equation:

6a^2+50=40a

We move all terms to the left:

6a^2+50-(40a)=0

a = 6; b = -40; c = +50;
Δ = b2-4ac
Δ = -402-4·6·50
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-20}{2*6}=\frac{20}{12}
=1+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+20}{2*6}=\frac{60}{12}
=5
$